Question

When the pressure of 5L of $N_2$ is double and its temperature is raised from 300K to 600K, the final volume of the gas would be:

• A. 10 L
• B. 5 L
• C. 15 L
• D. 20 L

Answer 1

Answer: (B)

5 L

Since $\frac{PV}{T}=nR=constant$

$\Rightarrow \frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\Rightarrow \frac{P_1\times 5}{300}=\frac{2P_1\times V_2}{600}$

$\Rightarrow V_2=5L$