Question

When the reverse potential in a semiconductor diode are $10V$ and $20V$, then the corresponding reverse currents are $25\mu A$ and $50\mu A$ respectively. The reverse resistance of junction diode will be

• A. $40\Omega$
• B. $4\times {10}^5\Omega$
• C. $40K\Omega$
• D. $4\times {10}^{-5}\Omega$

Answer 1

The correct option is B $4\times {10}^5\Omega$

Given:
$V_1=10V$
$V_2=20V$
$I_1=25\mu A=25\times {10}^{-6}\mu A$
$I_2=50\mu A=50\times {10}^{-6}\mu A$
Now, The reverse resistance of the diode is
$R=\frac{V_1}{I_1}=\frac{V_2}{I_2}$
$R=\frac{10}{25\times {10}^{-6}}$
$R=4\times {10}^5\Omega$