When the speed of a train is increased by 20%, it takes 20 min less to cover the same distance. What is the time taken to cover the same distance with the actual speed?

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1.5h

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2.5h

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Solution

The correct option is A 2h
Using product stability ratio method : D = S $\times$ T
Since speed has been increased by 20% or $\frac{1}{5}$ , so time will reduce by $\frac{1}{6}$ .
Now, $\frac{1}{6}$ of T (Time) = 20 min
T = 120 min = 2h

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When the speed of a train is increased by 20%, it takes 20 min less to cover the same distance. What is the time taken to cover the same distance with the actual speed?

The correct option is A 2hUsing product stability ratio method : D = S × T Since speed has been increased by 20% or 15, so time will reduce by 16. Now, 16 of T (Time) = 20 min T = 120 min = 2h

The correct option is A 2h
Using product stability ratio method : D = S $\times$ T
Since speed has been increased by 20% or $\frac{1}{5}$ , so time will reduce by $\frac{1}{6}$ .
Now, $\frac{1}{6}$ of T (Time) = 20 min
T = 120 min = 2h