Question

When the temperature is increased from 0${}^o$C to 273${}^o$C, in what ratio the average kinetic energy of molecules changes?

• A. 1
• B. 5
• C. 4
• D. 2

Answer 1

The correct option is D 2

Average K.E. $=\frac{3}{2}$ RT
At 0${}^o$C, average K.E. $=\frac{3}{2}\times R\times 273$
$[T=(0+273\left)K\right]$
At 273${}^o$C,
average K.E. $=\frac{3}{2}\times R\times (273+273)$
$=\frac{3}{2}\times R\times 2\times 273$
$\therefore$ Ratio = 2