The correct option is D 8,2
When the value of the azimuthal quantum number is 3, the maximum and the minimum values of the spin multiplicities are 8 and 2 respectively.
l=3 corresponds to f orbital.
In an f orbital, the maximum number of unpaired electrons can be 7.
Hence, S=72.
The maximum spin multiplicity is 2S+1=2×72+1=8.
In an f orbital, the minimum number of unpaired electrons can be 1.
Hence, S=12.
The minimum spin multiplicity is 2S+1=2×12+1=2.