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Hydrochloric Acid

When treated ...

Question

When treated with $c o n c . H C l, M n O_{2}$ yields a gas $(X)$ which further reacts with $C a (O H)_{2}$ to generate a white solid $(Y)$ . The solid $Y$ reacts with $d i l . H C l$ to produce the same gas $X$ . The solid $Y$ is :

C a O

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C a C l_{2}

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C a (O C l) C l

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C a C O_{3}

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Solution

The correct option is B $C a C O_{3}$
X : Carbon dioxide $C a C O_{3} + H C l \to C a C l_{2} + H_{2} O + C O_{2}$
Y : Calcium Carbonate $C a (O H)_{2} + C O_{2} \to C a C O_{3} + H_{2} O$
Z : $C a (H C O_{3})_{2}$ $C a C O_{3} + H_{2} O + C O_{2} \to C a (H C O_{3})_{2}$

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