Question

When gas $Y$ react with the black solid $Q$, then $Y$:

• A. oxidises $Q$
• B. decolourises $Q$
• C. dissociates $Q$
• D. reduces $Q$

Answer 1

The correct option is D reduces $Q$

$CuC{O}_3\underrightarrow{△}CuO+C{O}_2$

$\left(P\right)$ $\left(Q\right)$ $\left(X\right)$

$\downarrow$ $\downarrow$

(green solid) (black solid)

$3C{O}_2+3C\stackrel{△}{\to }6CO$

$\left(Y\right)$

$2CO+O_2⟶2C{O}_2$

$\left(X\right)$

$CO+CuO⟶Cu+C{O}_2$

$CO$ reduces $CuO$ to $Cu$ means that $Y$ reduces $Q$.

$\downarrow$

{good reducing agent}