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Question

When tuning forks A and B are sounded together, 5 beats per second are heard. The frequency of A is 250 Hz. On loading fork A with wax, 2 beats per second are produced with fork B. The frequency of fork B is -

A
255 Hz
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B
320 Hz
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C
245 Hz
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D
420 Hz
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Solution

The correct option is C 245 Hz
Given :

Initial frequency of tuning fork A, fA=250 Hz
Number of beats per second =5

|fAfB|=5 Hz.

After loading fork A with wax, the frequency of fork A will decrease.

Now, number of beats per second =2

Since, the number of beats per second decreases with the decrease in frequency of fork A.

fAfB=5 Hz

fB=fA5=2505=245 Hz

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