when two balanced dies are rolled simultaneously, the probability of getting the same number on both the dice is,

1

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\frac{1}{12}

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\frac{1}{6}

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\frac{1}{36}

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Solution

The correct option is C $\frac{1}{6}$
When two dice are rolled, total outcomes = $6 \times 6 = 36$
Outcomes with same number on both the die = $6$
Therefore, required probability = $\frac{6}{36} = \frac{1}{6}$

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when two balanced dies are rolled simultaneously, the probability of getting the same number on both the dice is,

The correct option is C 16When two dice are rolled, total outcomes = 6×6=36Outcomes with same number on both the die = 6Therefore, required probability = 636=16

The correct option is C $\frac{1}{6}$
When two dice are rolled, total outcomes = $6 \times 6 = 36$
Outcomes with same number on both the die = $6$
Therefore, required probability = $\frac{6}{36} = \frac{1}{6}$