When two bodies approach each other with different uniform speeds, the distance between them decreases by $120 m$ per every $1 m i n$ . If they move in the same direction, the distance between them increases by $90 m$ per every $1 m i n$ . The speeds of the bodies are respectively.

2 m / s

0.5 m / s

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3 m / s

2 m / s

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1.75 m / s

0.25 m / s

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2.5 m / s

0.5 m / s

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Solution

The correct option is D $1.75 m / s$ , $0.25 m / s$
The directions are represented as
$\to v_{1} \leftarrow v_{2}$
$v_{1} + v_{2} = \frac{120}{60} (m / s)$
$\Rightarrow v_{1} + v_{2} = 2 m / s$
$\to v_{1} \to v_{2}$
$\Rightarrow v_{1} - v_{2} = \frac{50}{1 \times 60} = 1.5 m / s$
$\Rightarrow v_{2} + v_{1} = 2$

$- v_{2} + v_{1} = 1.5$
$⟹ 2 v_{1} = 3.5$

$v_{1} = 1.75 m / s$
$v_{2} = 0.25 m / s$

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When two bodies approach each other with different uniform speeds, the distance between them decreases by 120m per every 1min. If they move in the same direction, the distance between them increases by 90m per every 1min. The speeds of the bodies are respectively.

The correct option is D 1.75m/s, 0.25m/sThe directions are represented as→v1←v2v1+v2=12060(m/s)⇒v1+v2=2 m/s→v1→v2⇒v1−v2=501×60=1.5 m/s⇒v2+v1=2−v2+v1=1.5⟹2v1=3.5v1=1.75 m/sv2=0.25 m/s

When two bodies approach each other with different uniform speeds, the distance between them decreases by $120 m$ per every $1 m i n$ . If they move in the same direction, the distance between them increases by $90 m$ per every $1 m i n$ . The speeds of the bodies are respectively.