When two capacitors of capacities 3- F and 6- F are connected in series and connected to 120 V- the potential difference across 3- F is-

The correct option is B 80V C=3× 69=2μ F V=120 V Q=CV=120× 2=240μ C V_3=Q3μ F=240μ C2μ F=80 V ...

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Byju's Answer

Standard XII

Physics

Parallel and Series Combination of Capacitors

When two capa...

Question

When two capacitors of capacities $3 μ F$ and $6 μ F$ are connected in series and connected to $120 V,$ the potential difference across $3 μ F$ is:

40 V

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60 V

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80 V

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180 V

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Solution

The correct option is B $80 V$
$C = \frac{3 \times 6}{9} = 2 μ F$
$V = 120 V$
$Q = C V = 120 \times 2 = 240 μ C$
$V_{3} = \frac{Q}{3 μ F} = \frac{240 μ C}{2 μ F} = 80 V$

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When two capacitors of capacities 3μF and 6μF are connected in series and connected to 120V, the potential difference across 3μF is:

The correct option is B 80VC=3×69=2μFV=120VQ=CV=120×2=240μCV3=Q3μF=240μC2μF=80V

When two capacitors of capacities $3 μ F$ and $6 μ F$ are connected in series and connected to $120 V,$ the potential difference across $3 μ F$ is:

The correct option is B $80 V$
$C = \frac{3 \times 6}{9} = 2 μ F$
$V = 120 V$
$Q = C V = 120 \times 2 = 240 μ C$
$V_{3} = \frac{Q}{3 μ F} = \frac{240 μ C}{2 μ F} = 80 V$