When two condensers of capacitance 1- F and 2- F are connected is series then the effective capacitance will be -

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Parallel and Series Combination of Capacitors

When two cond...

Question

When two condensers of capacitance $1 μ F$ and $2 μ F$ are connected is series then the effective capacitance will be :

\frac{2}{3} μ F

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\frac{3}{2} μ F

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3 μ F

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4 μ F

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Solution

The correct option is A $\frac{2}{3} μ F$
When two condenser are in series , the equivalent capacitance $C_{e q} = \frac{C_{1} C_{2}}{C_{1} + C_{2}} = \frac{1 \times 2}{1 + 2} = \frac{2}{3} μ F$

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When two condensers of capacitance 1μF and 2μF are connected is series then the effective capacitance will be :

The correct option is A 23μFWhen two condenser are in series , the equivalent capacitance Ceq=C1C2C1+C2=1×21+2=23μF

When two condensers of capacitance $1 μ F$ and $2 μ F$ are connected is series then the effective capacitance will be :

The correct option is A $\frac{2}{3} μ F$
When two condenser are in series , the equivalent capacitance $C_{e q} = \frac{C_{1} C_{2}}{C_{1} + C_{2}} = \frac{1 \times 2}{1 + 2} = \frac{2}{3} μ F$