When two dice are thrown at the same time, what is the probability that one dice shows up $3$ and the other shows up $6$ ?

\frac{1}{6}

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\frac{1}{3}

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\frac{1}{18}

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\frac{1}{9}

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Solution

The correct option is C $\frac{1}{18}$
When two dice thrown than the event of getting one dice show up 3 and the other shows up 6=2
$\Rightarrow (3, 6), (6, 3)$
Total numbers of outcomes= $6 \times 6 = 36$
$∴ P = \frac{n u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l n o . o f o u t c o m e s} = \frac{2}{36} = \frac{1}{18}$

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When two dice are thrown at the same time, what is the probability that one dice shows up 3 and the other shows up 6?

The correct option is C 118When two dice thrown than the event of getting one dice show up 3 and the other shows up 6=2⇒(3,6),(6,3)Total numbers of outcomes=6×6=36∴P=numberoffavorableoutcomesTotalno.ofoutcomes=236=118

When two dice are thrown at the same time, what is the probability that one dice shows up $3$ and the other shows up $6$ ?