When two magnets are placed $15 c m s$ and $20 c m s$ away from a deflection magnetometer on two arms, no deflection is observed. The ratio of magnetic dipole moments is

\frac{3}{4}

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\frac{9}{16}

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\frac{27}{64}

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\frac{81}{256}

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Solution

The correct option is A $\frac{27}{64}$
$\frac{M_{1}}{M_{2}} = {(\frac{d_{1}}{d_{2}})}^{3} = {(\frac{15}{20})}^{3} = {(\frac{3}{4})}^{3} = \frac{27}{64}$ . (using the standard result)

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When two magnets are placed 15 cms and 20 cms away from a deflection magnetometer on two arms, no deflection is observed. The ratio of magnetic dipole moments is

The correct option is A 2764M1M2=(d1d2)3=(1520)3=(34)3=2764. (using the standard result)

When two magnets are placed $15 c m s$ and $20 c m s$ away from a deflection magnetometer on two arms, no deflection is observed. The ratio of magnetic dipole moments is

The correct option is A $\frac{27}{64}$
$\frac{M_{1}}{M_{2}} = {(\frac{d_{1}}{d_{2}})}^{3} = {(\frac{15}{20})}^{3} = {(\frac{3}{4})}^{3} = \frac{27}{64}$ . (using the standard result)