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Byju's Answer

Standard XII

Physics

Ampere's Circuital Law

When two magn...

Question

When two magnets are placed $20 cms$ and $15 cms$ away on the two arms of a deflection magnetometer, it shows no deflection. The ration of magnetic moments is :

\frac{M_{1}}{M_{2}} = \frac{64}{27}

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\frac{M_{1}}{M_{2}} = \frac{4}{3}

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\frac{M_{1}}{M_{2}} = \frac{16}{9}

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none of these

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Solution

The correct option is A $\frac{M_{1}}{M_{2}} = \frac{64}{27}$
Magnetic moment ratio,
$\frac{M_{1}}{M_{2}} = \frac{d_{1}^{3}}{d_{2}^{3}}$
$\Rightarrow \frac{M_{1}}{M_{2}} = {(\frac{20}{15})}^{3}$
$\Rightarrow \frac{M_{1}}{M_{2}} = {(\frac{4}{3})}^{3}$
$\Rightarrow \frac{M_{1}}{M_{2}} = \frac{64}{27}$

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When two magnets are placed 20 cms and 15 cms away on the two arms of a deflection magnetometer, it shows no deflection. The ration of magnetic moments is :

The correct option is A M1M2=6427Magnetic moment ratio,M1M2=d31d32⇒M1M2=(2015)3⇒M1M2=(43)3⇒M1M2=6427

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