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Conventional current

When two resi...

Question

When two resistors with resistances $R_{1}$ and $R_{2}$ are connected in series, then the total equivalent resistance is

A

\frac{R_{1} R_{2}}{R_{1} + R_{2}}

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B

R_{1} + R_{2}

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C

1 / R_{1} + 1 / R_{2}

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D

R_{2} - R_{1}

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Solution

The correct option is B $R_{1} + R_{2}$
Components connected in series are connected along a single path, so the same current flows through all of the components. The current through each of the components is the same, and the voltage across the circuit is the sum of the voltages across each component. In a series circuit, every device must function for the circuit to be complete. One bulb burning out in a series circuit breaks the circuit. A circuit composed solely of components connected in series is known as a series circuit.
The total resistance of resistors in series is equal to the sum of their individual resistances. That is, $R_{t o t a l} = R_{1} + R_{2}$ . The current is given as $I = I_{1} = I_{2}$ .
Below is the diagrammatic representation of 2 resistors $R_{1} a n d R_{2}$ connected in series.

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