Question

When two symmetrical dice are rolled simultaneously, the probability that both the dice show even numbers is

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $\frac{1}{4}$
• D. $\frac{1}{8}$

Answer 1

Answer: (C)

$\frac{1}{4}$

Total cases when two dice are thrown $=6\times 6=36$
Even numbers between $1$ to $6$ is: $2,4,6$.
So cases when dice show even numbers on both dice $=3\times 3=9$
Probability that both the dice show even numbers is$=\frac{9}{36}=\frac{1}{4}$