When we clap our hands, the sound produced is best described by

p = p_{0} s i n (k x - ω t)

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p = p_{0} s i n k x c o s ω t

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p = p_{0} c o s k x s i n ω t

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p = \sum p_{o n} s i n (k_{n} x - ω_{n} t)

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Solution

The correct option is D $p = \sum p_{o n} s i n (k_{n} x - ω_{n} t)$
Here p denotes the change in pressure from the equilibrium value.

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Similar questions

Q. When we clap our hands, the sound produced is best described by
(a)

p = p_{0} \sin (k x - ω t)

(b)

p = p_{0} \sin k x \cos ω t

(c)

p = p_{0} \cos k x \sin ω t

(d)

p = \sum p_{0 n} \sin (k_{n} x - ω_{n} t)

.

Here p denotes the change in pressure from the equilibrium value.

Q. When we clap our hands, the sound produced is best described by Hence

p

denotes the change in pressure from the equilibrium value.

Q. If a polynomial, given by

p (x) = K (x - 1) (x - 2) & p (0) = 2,

Then the value of K is

The pressure variation equation of a sound wave propagating in a medium with pressure amplitude $P_{0}$ is

$P = P_{0} s i n ω (t - \frac{x}{v})$

Inference:

In the tube where this wave is propagating if we measure pressure, then the maximum pressure measured will be _{$P_{0}$}atm and Minimum pressure measured will be _{$- P_{0}$}atm as maximum $&$ minimum values of sin $θ$ is (+1/-1).

Q. The phase difference between two sound waves represented by

y_{1} = A_{1} sin (w t - k x)

and

y_{2} = A_{2} cos (w t - k x + π / 3)

is given by

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When we clap our hands, the sound produced is best described by

The correct option is D p=∑pon sin (knx−ωnt)Here p denotes the change in pressure from the equilibrium value.

The correct option is D $p = \sum p_{o n} s i n (k_{n} x - ω_{n} t)$
Here p denotes the change in pressure from the equilibrium value.