When $x^{3} - 6 x^{2} + 12 x - 4$ is divided by $x - 2$ , the remainder is

4

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0

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5

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6

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Solution

The correct option is A $4$
Let $p (x) =$ $x^{3} - 6 x^{2} + 12 x - 4$
and $g (x) =$ $x - 2$
$x - 2 = 0$
$\Rightarrow x = 2$
To find remainder, when $p (x)$ when by $g (x)$
By using remainder theorem, remainder is $p (2)$
thus, $p (2) = (2)^{3} - 6 (2)^{2} + 12 (2) - 4$
$= 8 - 24 + 24 - 4$
$= 4$

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