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Mole Concept

When Zn dus...

Question

When $Z n$ dust is added to sufficiently large volume of aqueous solution of copper sulphate. $3.175$ g of copper metal and $20$ J of heat is evolved. The $Δ H$ for the reaction is:
$Z n (s) + C u S O_{4} (a q) ⟶ Z n S O_{4} (a q) + C u (s)$
(Atomic weight of $Z n = 65.3$ , atomic weight of $C u = 63.5$ )

20 J

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200 J

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400 J

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65.3 J

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Solution

The correct option is C $400 J$
$C O S O_{4} + Z_{n} \to C O + Z n S O_{4}$
mass of $C o (m) = 3.175 g$ Molecular $(M) = 63.55$
no. of moles of $C o (O) = \frac{m}{M} = \frac{3.175}{63.55} = 0.04996 m o l$
$∴ 0.04996$ mol & $C o = 20 z$
So, 1 mol of $C O = \frac{20}{0.04996} = 400.32 J$

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Similar questions

Z n_{(} s) + C u S O_{4} (a q) \to Z n S O_{4} (a q) + C u_{(} s)

Z n + C u S O_{4} = C u + Z n S O_{4}

10 g

200 m L

C u S O_{4 (a q)} + Z n_{(s)} \to Z n S O_{4 (a q)} + C u_{(s)}

1.0 M

(H^{+})

9650

3.175 g

C u = 63.5

1.19

50

3 \times 10^{21}

A l = 27; C u = 63.55, Z n = 65.0

N_{A} = 6 \times 10^{23}

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