Which among the following has maximum number of atoms?

14 g o f N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 g o f C H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22 g o f C O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 g o f C_{2} H_{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $15 g o f C_{2} H_{6}$
Mole of $N_{2} = \frac{14}{28} = 0.5$
Mole of atoms of $N_{2} = 0.5 \times 2 = 1$
Mole of $C H_{4} = \frac{8}{16} = 0.5$
Mole of atoms of $C H_{4} = 0.5 \times 5 = 2.5$
Mole of $C O_{2} = \frac{22}{44} = 0.5$
Mole of atoms of $C O_{2} = 0.5 \times 3 = 1.5$
Mole $C_{2} H_{6} = \frac{15}{30} = 0.5$
Mole of atoms of $C_{2} H_{6} = 0.5 \times 8 = 4$

Suggest Corrections