Which among the following relations is correct?

K_{a_{1}} < K_{a_{2}} < K_{a_{3}}

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K_{a_{1}} > K_{a_{2}} > K_{a_{3}}

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K_{a_{1}} = K_{a_{2}} = K_{a_{3}}

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K_{a_{1}} > K_{a_{3}} > K_{a_{2}}

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Solution

The correct option is B $K_{a_{1}} > K_{a_{2}} > K_{a_{3}}$
${p K a}_{1} = 2.12 \Rightarrow - l o g {K a}_{1} = 2.12 \Rightarrow {K a}_{1} = 10^{- 2.12}$
${p K a}_{2} = 7.21 \Rightarrow - l o g {K a}_{2} = 7.21 \Rightarrow {K a}_{2} = 10^{- 7.21}$
${p K a}_{3} = 12.32 \Rightarrow - l o g {K a}_{3} = 12.32 \Rightarrow {K a}_{3} = 10^{- 12.32}$

So, ${K a}_{1} > {K a}_{2} > {K a}_{3}$

The answer will be option $B$ .

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