Which among the following will give tertiary alcohol on acid hydration?

CH₃-CH=CH-CH₃

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(CH₃)₂C=CH₂

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CH₃-C(CH₃)=CH-CH₃

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CH₃-CH=CH₂

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Solution

The correct options are
B
(CH₃)₂C=CH₂

C
CH₃-C(CH₃)=CH-CH₃

But-2-ene gives only secondary alcohols on acid hydration while propene can give a mixture of secondary and primary alcohols.

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Similar questions

A g N O_{3}

C H_{3} - C H | C H_{3} - C H_{2} - C H | C H_{3} - C H | C H_{3} - C H_{3}

C H_{3} - C H | C H_{3} - C H | C H_{3} - C H_{3}

I U P A C

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H_{2} - C H = C H_{2}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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