Which are free radical reactionsI- CH3 - CH - CH2 -HBr CH3 - CH2 - CH2 BrII- CH3 - CH - CH2 -HBr - CH3 -CHBr -CH3III- CH3 - CH - CH2 -Cl2 - ClCH2 -CH - CH2IV- CH3 - CH3 -Cl2 - ClCH2 - CH3

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Standard XIII

Chemistry

Addition Reactions

Which are fre...

Question

Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

Only I

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I, III and IV

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III and IV

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IV and I

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Solution

The correct option is B
I, III and IV

Anti Markownikoff rule and chlorination of $s p^{3}$ carbon undergoes by free radical mechanism

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Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Q. Complete table.

Chemical reaction	Product	$I U P A C$ name of the product
$C H_{2} = C H_{2} + C l_{2}$	........	........
$C H_{2} = C H_{2} + H C l$	..........	.........
$C H_{3} - C h = C H_{2} + H_{2}$	..........	..........
$C H_{3} - C H = C H - C H_{3} + H B r$	...........	........

Q. Identify the type of the following reaction of carbon compounds.
a. CH₃ -CH₂ -CH₂-OH → CH₃ -CH₂ -COOH
b. CH₃ -CH₂ -CH₃ → 3CO₂ + 4H₂O
c. CH₃ -CH = CH -CH₃ + Br₂ → CH₃ -CHBr - CHBr -CH₃
d. CH₃ -CH₃ + Cl₂→ CH₃ -CH₂ -Cl + HCl
e. CH₃-CH₂ -CH₂ -CH₂ -OH → CH₃ -CH₂ -CH=CH₂ + H₂O
f. CH₃-CH₂ -COOH + NaOH → CH₃ -CH₂ -COO - Na⁺ + H₂O
g. CH₃ -COOH + CH₃ -OH → CH₃ -COO- CH₃ + H₂O

C H_{3} - C H = C H_{2} + H B r \to

-------- the product is

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Which are free radical reactions I.CH3−CH=CH2+HBrPeroxide−−−−−→CH3−CH2−CH2BrII.CH3−CH=CH2+HBr→CH3−CHBr−CH3III.CH3−CH=CH2+Cl2→ClCH2−CH=CH2IV.CH3−CH3+Cl2→ClCH2−CH3

The correct option is B I, III and IV Anti Markownikoff rule and chlorination of sp3 carbon undergoes by free radical mechanism

The correct option is B
I, III and IV

Anti Markownikoff rule and chlorination of $s p^{3}$ carbon undergoes by free radical mechanism