The correct option is C ∠HCD
For methane derivatives, instead of directing equivalent sp3 orbitals toward all four substituents, orbitals get oriented such that more electronegative element occupies the orbital having less s character and vice versa [Bent's rule].
(Electronegativity of given elements: F>Cl>H>D)
As a result of this, ∠HCD becomes the largest (more s character) and ∠ClCF becomes the smallest (more p character).