Which carbon atom will show minimum electronegativity -

H $^{1} C$ $\equiv$ $^{2} C$ - C $^{3} H$ - C $^{4} H$ - C $^{5} H$

Fifth

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Third

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First

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Second

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Solution

The correct option is A
Fifth

${s p}^{3}$ - hybridised carbon has 25% s character , 75% p character.

${s p}^{2}$ $\to$ 33.3% s character, 66.6% p character

sp $\to$ 50% s and 50% p

More the s character, more is the electronegativity.

H $C^{1}$ $\equiv$ $C^{2}$ - $C^{3} H$ = $C^{4} H$ - $C^{5} H_{3}$

1 & 2 $\to$ sp

$5^{t h}$ carbon is ${s p}^{3}$

3 & 4 $\to$ ${s p}^{2}$

Suggest Corrections

Similar questions

Which carbon atom will show minimum electronegativity -

H $^{1} C$ $\equiv$ $^{2} C$ - C $^{3} H$ - C $^{4} H$ - C $^{5} H$

C 1 H_{3} - C 2 H = C 3 = C 4 H_{2}

1 H C \equiv 2 C 3 C H = 4 C H 5 C H_{3}

E_{H - H} = 104.2 k c a l m o l^{- 1}

E_{C - C} = 83.1 k c a l m o l^{- 1}

E_{C - H} = 98.8 k c a l m o l^{- l}

X_{H} = 2.1.

H - H, C - C

C - H

104.2, 83.1

98.8

m o l^{- 1}

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