Which compound among the following has the lowest oxidation number of Mn?
$K M n O_{4}, K_{2} M n O_{4}, M n O_{2}$ and $M n_{2} O_{3}$ .

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Solution

$M n_{2} O_{3}$ has the lowest oxidation number of Mn.
The oxidation number of Mn in $M n_{2} O_{3}$ is $+ 3$ .
Let X be the oxidation number of Mn in $M n_{2} O_{3}$ .
$2 X + 3 (- 2) = 0$
$2 X - 6 = 0 = 0$
$X = + 3$ .
The oxidation number of Mn in $K M n O_{4}, K_{2} M n O_{4}, M n O_{2}$ is $+ 7$ , $+ 6$ and $+ 4$ respectively.

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