Question

Which compound amongst the following has the highest oxidation number of $Mn$?

• A. $KMn{O}_4$
• B. $K_{2}Mn{O}_4$
• C. $Mn{O}_2$
• D. $M{n}_2{O}_3$

Answer 1

The correct option is A $KMn{O}_4$

Let the oxidation number of $Mn$ be $x$.

Oxidation state of $K=+1$, $O=-2$.

(A) $KMn{O}_4$: $1+x+4\times (-2)=0$

$x=+7$

(B) $K_{2}Mn{O}_4$: $2\times 1+x+4\times (-2)=0$

$x=+6$

(C)$Mn{O}_2$: $x+2\times (-2)=0$

$x=+4$

(D) $M{n}_2{O}_3$: $2x+3\times (-2)=0$

$x=+3$

therefore highest oxidation number of $Mn$ is +7 in $KMn{O}_4$