Question

Which compound has a planar structure?

• A. $Xe{F}_4$
• B. $Xe{O}_3$
• C. $Xe{O}_2{F}_2$
• D. $Xe{O}_4$

Answer 1

The correct option is A $Xe{F}_4$

In $Xe{F}_4$ molecule, the central atom $\left(Xe\right)$ has 6 electron pairs around it in which 4 electron pairs are bonding pairs and 2 electron pairs are lone pairs.
So the geometry is octahedral but the shape is square planar due to the two lone pairs on it. The two lone pairs repel each other, so they are placed at an angle of ${180}^o$ and the shape is square planar.