Question

Which compounds has planar structure ?

• A. XeOF₂
• B. XeO₄
• C. XeF₄
• D. XeO₂F₂

Answer 1

The correct option is C XeF₄

Hybridization = Number of σ-bonds + number of lone paires
(A) $Xe{F}_4$: Hybridization $=4+2=s{p}^3{d}^2$(square planar)


(B) $XeO{F}_2$: hybridization $=3+2=s{p}^{3}d$ (T shaped)


(C) $Xe{O}_2{F}_2:$ Hybridization $=4+1=s{p}^{3}d$ (see saw structure)


(D) $Xe{O}_4:$ Hybridization $=4+0=s{p}^3$ (tetrahedral)