Question

Which has maximum number of atoms?

• A. 24 g of C (12)
• B. 56 g of Fe (56)
• C. 27 g of Al (27)
• D. 108 g of Ag (108)

Answer 1

The correct option is A

24 g of C (12)

$24gC=\frac{24}{12}mole=2mole=2\times N_{0}atoms$

$56gFe=\frac{56}{56}mol=1mol=N_{0}atoms$

$27gAl=\frac{27}{27}mol1mol=N_{0}atoms$

$108gAg=\frac{108}{108}mol=1mol=N_{0}atoms$