Which has minimum number of unpaired d-electrons?

F e^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C o^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C o^{2 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M n^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C o^{2 +}$
$F e^{3 +} = 4 s^{0} 3 d^{5}$ number of unpaired $e^{-} = 5$
$C o^{3 +} = 4 s^{0} 3 d^{6}$ number of unpaired $e^{-} = 4$
$C o^{2 +} = 4 s^{0} 3 d^{7}$ number of unpaired $e^{-} = 3$
$M n^{3 +} = 4 s^{0} 3 d^{4}$ number of unpaired $e^{-} = 4$
Minimum number of unpaired d- $e^{-} s$ is $3 \Rightarrow C o^{2 +}$

Suggest Corrections

Similar questions

M n^{3 +}

[A r] 3 d^{6}

(A t o m i c N u m b e r : M n = 25, F e = 26, C o = 27, N i = 28)

S c = 21, F e = 26, V = 23, N i = 28)

F e^{3 +}, F e^{2 +}, F e^{+}

Join BYJU'S Learning Program