Which has the least bond angle

NH₃

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BeF₂

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H₂O

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CH₄

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Solution

The correct option is C
H₂O

Due to $l_{p} - l_{p}$ repulsions, bond angle in $H_{2} O$ is lower $(104^{o} {.5}^{o})$ than that in $N H_{3} (107^{o})$ and $C H_{4} (109^{o} 28') . B e F_{2}$ on the other hand, has sp-hybridization and hence has a bond angle of $180^{o}$ .

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Similar questions

C H_{4}, N H_{3} a n d H_{2} O

Consider the molecules $C H_{4}$ , $N H_{3}$ and $H_{2} O$ . Which of the given statements is false?

C H_{4}, N H_{3}, H_{2} O, B F_{3}, C_{2} H_{2}

N H_{3}, N H_{2}^{-}, N H_{4}^{+}

C H_{4}

N H_{3}

H_{2} O

C H_{4}, N H_{3}, H_{2} O, H F

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