Which impurity (as a salt) is associated with table salt obtained from sea-water?

N a H C O_{3}

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M g C O_{3}

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M g C l_{2}

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N a I

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Solution

The correct option is D $M g C l_{2}$
Sea water contains $M g C l_{2}$ brine so salt made from sea water contains this as impurity.
sea salt:
Chloride $(C l^{-})$ 55.03%
Sodium $(N a^{+})$ 30.59%
Sulfate $(S O_{4}^{2 -}$ 7.68%
Magnesium $(M g^{2 +})$ 3.68%
Calcium $(C a^{2 +})$ 1.18%
Potassium $(K^{+})$ 1.11%
Bicarbonate $(H C O_{3}^{-})$ 0.41%
Bromide $(B r^{-})$ 0.19%

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Similar questions

Q. Table salt is contaminated with

N a H C O_{3}

due to presence of

M g C l_{2}

as impurity (from sea).
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Chloride $(C l^{-})$	55.03%
Sodium $(N a^{+})$	30.59%
Sulfate $(S O_{4}^{2 -}$	7.68%
Magnesium $(M g^{2 +})$	3.68%
Calcium $(C a^{2 +})$	1.18%
Potassium $(K^{+})$	1.11%
Bicarbonate $(H C O_{3}^{-})$	0.41%
Bromide $(B r^{-})$	0.19%

Which impurity (as a salt) is associated with table salt obtained from sea-water?

The correct option is D MgCl2Sea water contains MgCl2 brine so salt made from sea water contains this as impurity.sea salt: Chloride (Cl−) 55.03% Sodium (Na+) 30.59% Sulfate (SO2−47.68% Magnesium (Mg2+)3.68% Calcium (Ca2+)1.18% Potassium (K+)1.11% Bicarbonate (HCO−3)0.41% Bromide (Br−)0.19%