Which ion has the largest radius?

S e^{2 -}

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F^{-}

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O^{2 -}

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R b^{+}

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Solution

The correct option is C $S e^{2 -}$
For species having same balance electron $.$ Radii is inversely proportional to protons $.$
So $,$ $r \propto \frac{e^{-}}{p},$
Hence $,$ $r = {s e}^{2 -} > {R b}^{+} .$

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