Which is correct for mitotic cell cycle?

S \to G_{1} \to G_{2} \to M \to S

No worries! We‘ve got your back. Try BYJU‘S free classes today!

G_{2} \to G_{1} \to S \to M \to G_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

G_{1} \to G_{1} \to S \to M \to G_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

G_{1} \to S \to G_{2} \to M \to G_{1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $G_{1} \to S \to G_{2} \to M \to G_{1}$
D. $G_{1}$ - S - $G_{2}$ - M - $G_{1}$
EXPLANATION: The cell cycle is a four-stage process in which the cell increases in size in $G_{1}$ phase, copies its DNA in S phase, prepares to divide in $G_{2}$ phase and divides in M phase. The stages $G_{1}$ , S and $G_{2}$ make up interphase, which accounts for the span between cell divisions.

Suggest Corrections

Similar questions

Q. If n geometric means between a and b be

G_{1}, G_{2}, . . . . . . . G_{n}

and a geometric mean be G, then the true relation is

Q. Mitotic cell cycle is divided typically into four phases,

G_{1}

, S,

G_{2}

and M. Considering a mitotic cycle time of

18

hours, the distribution of period of time(in hours) for each of these phase will be.

G_{1}

_{2}

If n geometric means between a and b be $G_{1}, G_{2}, . . . . G_{n}$ and a geometric mean of a and b be G, then the true relation is

G_{1}, S

and

G_{2}

are stages of _________.

Two planets have the same average density but their radii are $R_{1}$ and $R_{2}$ . If acceleration due to gravity on these planets be $g_{1}$ and $g_{2}$ respectively, then

Join BYJU'S Learning Program