Question

Which is more reactive towards $S_E$ and explain?

Answer 1

(i) II is more reactive.

Both $-OH$ and $-O^{-}$ are activating groups towards $S_E$ reaction. However, wWhile drawing resonating structures, (I) will have +ve charge on O atom whereas in II O will be neutral. Hence, the second one stabilises the intermediate more than the first one.

So, II is more reactive.

ii) II is more reactive

I has one activating as well as deactivating group. $N{O}_2$ is an electron withdrawing group. While II has only activating group towards $S_E$ reaction.

Hence, II will be more reactive.