Which is not the correct relation between different current gain - - - - - of transistor amplifier -

The correct options are A β = α/ 1 α B α = β/β + 1 For a transistor amplifier β #160; = ( ΔI_C/ΔI_B)_V_CE = constant α #160; = ( ΔI_ ...

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Byju's Answer

Standard XII

Physics

Transistor as an Amplifier

Which is not ...

Question

Which is not the correct relation between different current gain $(α, β, γ)$ of transistor amplifier :-

α = \frac{β}{β + 1}

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β = \frac{α}{1 - α}

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β = γ + 1

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α = \frac{β}{γ}

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Solution

The correct options are
A $β = \frac{α}{1 - α}$
B $α = \frac{β}{β + 1}$
For a transistor amplifier-
$β = {(\frac{Δ I_{C}}{Δ I_{B}})}_{V_{C E} = constant}$
$α = {(\frac{Δ I_{C}}{Δ I_{E}})}_{V_{C B} = constant}$
Also,
$Δ I_{B} = Δ I_{E} - Δ I_{C}$
Therefore, $β = (\frac{Δ I_{C}}{Δ I_{B}}) = (\frac{Δ I_{C}}{Δ I_{E} - Δ I_{C}}) = (\frac{Δ I_{C} / Δ I_{E}}{1 - Δ I_{C} / Δ I_{E}}) = \frac{α}{1 - α}$
From this we can have, $α = \frac{β}{1 + β}$
So, option (A) & (B) both are correct.

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Which is not the correct relation between different current gain (α,β,γ) of transistor amplifier :-

The correct options are A β=α1−α B α=ββ+1For a transistor amplifier-β=(ΔICΔIB)VCE= constantα=(ΔICΔIE)VCB= constantAlso,ΔIB=ΔIE−ΔICTherefore, β=(ΔICΔIB)=(ΔICΔIE−ΔIC)=(ΔIC/ΔIE1−ΔIC/ΔIE)=α1−αFrom this we can have, α=β1+βSo, option (A) & (B) both are correct.

Which is not the correct relation between different current gain $(α, β, γ)$ of transistor amplifier :-