Question

Which is stronger reducing agent $F{e}^{2+}$ (or) $C{r}^{2+}$. Why?

Answer 1

Reducing agent :- The tendency to loose electrons or to undergoes oxidation easily.

$\to$ It based on the number of maximum electrons that it can given out

$\to$ We know for $Cr$ $+6$ is maximum, So ${Cr}^{+2}$ can lose ${4e}^{-}$

$\to$ But for $Fe$ $+3$ is maximum, So ${Fe}^{+2}$ can lose only ${1e}^{-}$

Ans :- ${Cr}^{+2}$