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Introduction to d and f Block Elements

Which is the ...

Question

Which is the anhydride of ${H N O}_{3}$ out of $N_{2} O, N O, N_{2} O_{5}$ ?

N_{2} O_{5}

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N O

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N_{2} O

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{H N O}_{3}

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Solution

The correct option is A $N_{2} O_{5}$
The anhydride of $H N O_{3}$ is $N_{2} O_{5}$ (oxidation number of the element $(N)$ in oxyacid and its anhydride remains same).

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Similar questions

N_{2} O_{5} ⟶ 2 N O_{2} + 1 / 2 O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

k_{1}, k_{2}

k_{3}

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2} .

G i v e n : - \frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}]

A n d \frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}]

The relation between $K_{1}, K_{2}$ and $K_{3}$ is

H_{2} N_{2} O_{2}, H N O_{2}, H N O_{3}

N_{2} O_{5}, N_{2} O, N O, N_{2} O_{3}

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2},

\frac{- d}{d t} [N_{2} O_{5}] = k_{1} [N_{2} O_{5}], \frac{d}{d t} [N O_{2}] = k_{2} [N_{2} O_{5}] a n d

\frac{d}{d t} [O_{2}] = k_{3} [N_{2} O_{3}],

N_{2} O

N_{2} O_{5} (g) ⇌ 2 {N O}_{2} (g) + \frac{1}{2} O_{2} (g)

D

P_{0}

N_{2} O_{5} (g)

M

N_{2} O_{5}

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