wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Which is the correct expression that relates change in entropy with the change in pressure for an ideal gas at constant temperature?

A
S=nRT lnP1P2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
S=T(P2P1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
S=nR ln(P1P2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
S=RT ln(P1P2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C S=nR ln(P1P2)
We know that entropy change in an isothermal process for an ideal gas is given as:
S=nR ln(V2V1)

Since P1V1=P2V2 according to Boyle's law at constant temperature we can also write,
S=nR ln(P1P2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon