Which is the correct order of acidic strength of the following acids?

C H_{3} C H_{2} C O O H > C H_{2} = C H - C O O H > H C \equiv C - C O O H

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C H_{3} C H_{2} C O O H < C H_{2} = C H - C O O H > H C \equiv C - C O O H

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C H_{3} C H_{2} C O O H > C H_{2} = C H - C O O H < H C \equiv C - C O O H

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C H_{3} C H_{2} C O O H < C H_{2} = C H - C O O H < H C \equiv C - C O O H

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Solution

The correct option is D $C H_{3} C H_{2} C O O H < C H_{2} = C H - C O O H < H C \equiv C - C O O H$

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Similar questions

C H_{3} C H_{2} C O O H

C H_{2} = C H - C O O H

H C \equiv C - C O O H

C H \equiv C - C O O H; C H_{2} = C H - C O O H; C H_{3} C H_{2} C O O H

{C l}_{3} C C O O H > {C l}_{2} C H C O O H > C l {C H}_{2} C O O H

{C H}_{3} C H_{2} C O O H > {(C H}_{3})_{2} C H C O O H > {(C H}_{3})_{3} C C O O H

F_{2} C H_{2} C O O H > F C H_{2} C O O H > C l {C H}_{2} C O O H

H C O O H, {C H}_{3} C O O H, C_{2} H_{5} C O O H

C_{3} H_{7} C O O H

H C = C - C O O H

C H_{2} = C H - C O O H

C H_{3} - C H_{2} - C O O H

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