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Question

Which is the incorrect statement among the following?
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A
X is isopropyl bromide, Y is n-propyl bromide
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B
X and Y are positional isomers
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C
Formation of X is electrophilic addition
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D
Formation of Y is electrophilic addition
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Solution

The correct option is D Formation of Y is electrophilic addition
Solution:- (D) Formation of Y is electrophilic addition
CH3CH=CH2HBr−−CH3Br|CHCH3(X) Electrophilic addition (Follows Markovnikov rule)
CH3CH=CH2HBr/(C6H2CO)2O2−−−−−−−−−−−CH3CH2CH2Br(Y) Free radical addition (Follows anti-Markovnikov rule)
Hence (D) is incorrect.

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