Which is the incorrect statement among the following?

X is isopropyl bromide, Y is n-propyl bromide

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X and Y are positional isomers

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Formation of X is electrophilic addition

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Formation of Y is electrophilic addition

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Solution

The correct option is D Formation of Y is electrophilic addition
Solution:- (D) Formation of $Y$ is electrophilic addition
$C H_{3} - C H = C H_{2} H B r - -- \to C H_{3} - B r | C H - C H_{3} (X) \Rightarrow$ Electrophilic addition (Follows Markovnikov rule)
$C H_{3} - C H = C H_{2} H B r / {(C_{6} H_{2} C O)}_{2} O_{2} - ----------- \to C H_{3} - C H_{2} - C H_{2} - B r (Y) \Rightarrow$ Free radical addition (Follows anti-Markovnikov rule)
Hence $(D)$ is incorrect.

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Similar questions

S_{N} 1

Assertion (A): In addition if HBr to propene, isopropyl bromide is major

product but n - propyl bromide is minor product

Reason(R): Isopropyl carbonium ion is more stable than n - propyl carbonium ion

2^{o}

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