The correct option is D 151
The least number which is divisible by 12, 16, 24 and 36 is the LCM of 12, 16, 24 and 36.
12 = 2 × 2 × 3
16 = 2 × 2 × 2× 2
24 = 2 × 2 × 2 × 3
36 = 2 × 2 × 3 ×3
LCM of 12, 16, 24 and 36 = 2 × 2 × 2 × 2 × 3 × 3 = 144
Therefore, least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case = 144 + 7 = 151.