Which monomer is responsible for the flexibility property in $P H B V$ ?

H O - C H | C H_{3} - C H_{3} - C O O H

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H O - C H | C H_{2} - C H_{3} - C H_{2} - C O O H

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H O - C H | C H_{3} - C H_{2} - C H_{2} - C O O H

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H O - C H | C H_{2} - C H_{3} - C H_{2} - C H O

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Solution

The correct option is C $H O - C H | C H_{2} - C H_{3} - C H_{2} - C O O H$
PHVB is a co-polymer. The monomers, 3-hydroxybutanoic acid and 3-hydroxypentanoic acid, are joined by ester bonds; the back bone of the polymer is made up of carbon and oxygen atoms. The property of the PHBV depends upon the ratio of these two monomers in it. 3-hydroxybutanoic acid provides stiffness while 3-hydroxypentanoic acid promotes flexibility.
therefore option B is correct.

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C H_{3} - C H = C H - C H_{2} O H P C C - -- \to Product

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

E_{1}

C H_{3} - H O | C H - C H_{3}

C H_{3} - H O | C | C H_{3} H - C H_{3}

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C H_{3} - C H_{2} - C H_{2} O H

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