Question

Which number should come in place of X, to have a constant sum along sides and diagonal?
$\begin{array}{ccc}4& 3& 8\\ 9& \times & 1\\ 2& 7& 6\end{array}$

• A. 3
• B. 4
• C. 5
• D. 6

Answer 1

The correct option is C 5

Side wise sum = 4+3+8 = 2+7+6 = 4+9+2 = 8+1+6 = 15.
Since all sides follow the pattern of having equal sum of 15, so its diagonals also have the sum as 15 as given in the question.
So, the number “5” should come in place “x” to have a sum of 15, i.e. 4+5+6 = 8+5+2 = 15.