Which odd number needs to be taken out to form a cube number?
$5 + 7 + 9 + 11$

7

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5

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9

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11

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Solution

The correct option is A $5$
We know,
$1 = 1 = 1^{3}$ ,
$3 + 5 = 8 = 2^{3}$ ,
$7 + 9 + 11 = 27 = 3^{3}$ .
Therefore, $5$ must be taken out to form a cube number, $3^{3} = 27$ .
Hence, option $B$ is correct.

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