Which of following cell can produce more electrical work.

P t, H_{2} | N H_{4} C l | | 0.1 M C H_{3} C O O H | H_{2}, P t

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P t, H_{2} | 0.1 M H C l | | 0.1 M N a O H | H_{2}, P t

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P t, H_{2} | 0.1 M H C l | | 0.1 M C H_{3} C O O K | H_{2}, P t

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P t, H_{2} | 0.1 M C H_{3} C O O K | | 0.1 M H C l | H_{2}, P t

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Solution

The correct option is D $P t, H_{2} | 0.1 M C H_{3} C O O K | | 0.1 M H C l | H_{2}, P t$
$E_{c e l l} = \frac{0.0591}{1} l o g \frac{[H^{+}]_{a}}{[H^{+}]_{c}}$
For $E_{c e l l}$ to be highest, $[H^{+}]_{a}$ should be lower and $[H^{+}]_{c}$ should be higher and that's why anode compartment should be more basic and cathodic compartment should be acidic.

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