Question

Which of the above synthetic scheme can be used to prepare the oct-2,7-dione?

• A. React acetylene with $NaN{H}_2/N{H}_3$; add half of an equivalent of 1,4-dibromobutane; then add $H_{2}O/H_{2}S{O}_4/HgS{O}_4$
• B. React 1,6-octadiene with $O_3$ followed by $Zn$-acetic acid
• C. React 1,2-dimethylcyclohexene with $KMn{O}_4/H^{+}$
• D. Both (a) and (c) may work.

Answer 1

The correct option is C React 1,2-dimethylcyclohexene with $KMn{O}_4/H^{+}$

1,2-dimethyl cyclo hexene reacts with $KMn{O}_4/H^{+}$ to form our desired product Oct-2,7-dione.

In this process double bond in 1,2-dimethyl cyclo hexene undergo oxidative cleavage and gives two keto groups.