Which of the compound will liberate oxygen when reacted with water?

N a_{2} O_{2}

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K O_{2}

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N a_{2} O

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C s_{2} O_{2}

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Solution

The correct option is C $K O_{2}$
(A) Sodium peroxide reacts with water to form sodium hydroxide and hydrogen peroxide.
$N a_{2} O_{2} + 2 H_{2} O \to 2 N a O H + H_{2} O_{2}$
(B) Potassium dioxide $K O_{2}$ reacts with water to liberate oxygen.
$2 K O_{2} + 2 H_{2} O \to 2 K O H + H_{2} O_{2} + O_{2}$
(C) Sodium oxide $N a_{2} O$ reacts with water to form sodium hydroxide.
$N a_{2} O + H_{2} O \to 2 N a O H$

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